Related » Graph » Number Line » Examples » Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!How To Graph A Circle Using Standard Form If your circle equation is in standard or general form, you must first complete the square and then work it into centerradius form Suppose you have this equation x2 y2 − 8x 6y − 4 = 0 x 2 y 2 8 x 6 y 4 = 0 Rewrite the equation so that all your x x terms are in the first parenthesesQuestion Graph X^2y^2=4 In 3D, Aka Xyz Aka R3 This problem has been solved!
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X^2+y^2=4 graph-Directrix x = 17 4 x = 17 4 Select a few x x values, and plug them into the equation to find the corresponding y y values The x x values should be selected around the vertex Tap for more steps Substitute the x x value 2 2 into f ( x) = √ − x 4 f ( x) = x 4 In this case, the point is ( 2, ) ( 2, ) how can i draw graph of z^2=x^2y^2 on matlab Follow 131 views (last 30 days) Show older comments Rabia Kanwal on Vote 0 ⋮ Vote 0 Commented Walter Roberson on Accepted Answer Star Strider 0 Comments Show Hide 1 older comments Sign in to comment Sign in to answer this question
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Graph x^2 (y2)^2=4 x2 (y − 2)2 = 4 x 2 ( y 2) 2 = 4 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h h representsWhen you will draw the graph you will get a circle the radius of this circle is 2 this is an equation of a circle Thank you sooooo much!Unlock StepbyStep plot x^2y^2x Extended Keyboard Examples
How to plot 3 dimensional graph for x^2 y^2 = 1?Start your free trial In partnership withAnswer by lwsshak3 () ( Show Source ) You can put this solution on YOUR website!
Graph the parabola, y =x^21 by finding the turning point and using a table to find values for x and yA hyperbola is a type of conic section that looks somewhat like a letter x A hyperbola is a set of all points P such that the difference between the distances from P to the foci, F 1 and F 2, are a constant KBefore learning how to graph a hyperbola from its equation, get familiar with the vocabulary words and diagrams belowThe plot command will generate a plot of almost any function or relation found in high school and undergraduate college mathematics It will plot functions given in the form y = f(x), such as y = x 2 or y = 3x 1, as well as relations of the form f(x,y) = g(x,y), such as x 2 y 2 = 4
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Plane z = 1 The trace in the z = 1 plane is the ellipse x2 y2 8 = 1 1 Answer1 One may recognize an ellipsoid, a particular quadric surface If one chooses a cartesian coordinate system, such that the origin is the center of the ellipsoid, and the coordinate axes are axes of the ellipsoid, the implicit equation of the ellipsoid has the standard form x 2 a 2 y 2 b 2 z 2 c 2 = 1Answered 3 years ago Author has 33K answers and 15M answer views There is no radius because this is not a circle Factorize x^2y^2=0 (xy) (xy)=0 Now because of this, your graph will be where either xy=0, and where xy=0 As you can tell, those are going to be a pair of lines, intersecting at (0,0)
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyPlotting graphics3d Share Improve this question Follow asked Nov 29 '15 at 533 user user 11 1 1 gold badge 1 1 silver badge 2 2 bronze badgesGraph x^24y^2=4 x2 − 4y2 = 4 x 2 4 y 2 = 4 Find the standard form of the hyperbola Tap for more steps Divide each term by 4 4 to make the right side equal to one x 2 4 − 4 y 2 4 = 4 4 x 2 4 4 y 2 4 = 4 4 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola
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Here is the graph of the surface and we've tried to show the region in the \(xy\)plane below the surface Here is a sketch of the region in the \(xy\)plane by itself By setting the two bounding equations equal we can see that they will intersect at \(x = 2\) and \(x = 2\)Graph the ellipse and its foci x^2/9 y^2/4=1 standard forms of ellipse (xh)^2/a^2 (yk)^2/b^2=1 (horizontal major axis),a>b (yk)^2/a^2 (xh)^2/b^2=1 (vertical major axis),a>b given ellipse has horizontal major axis center (0,0)I am already using it and I only can plot in 2 dimensional graph Can someone help me with this problem?
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Sin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculationsAn ellipsoid is a surface described by an equation of the form x2 a2 y2 b2 z2 c2 = 1 Set x = 0 to see the trace of the ellipsoid in the yz plane To see the traces in the xy and xz planes, set z = 0 and y = 0, respectively Notice that, if a = b, the trace in the xy plane is a circleAs people have said, it is a circle Because it is just x^2 and y^2 and not say (x 2)^2 it has centre (0,0) the origin The number 4 on the right hand side is the square of the radius, so it is a circle
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A sphere is the graph of an equation of the form x 2 y 2 z 2 = p 2 for some real number p The radius of the sphere is p (see the figure below) Ellipsoids are the graphs of equations of the form ax 2 by 2 cz 2 = p 2, where a, b, and c are all positiveQuestion 5480 Could someone help me graph y=x^24 Answer by Edwin McCravy () ( Show Source ) You can put this solution on YOUR website!To graph an ordered pair of numbers, we begin by constructing a pair of perpendicular number lines, called axes The horizontal axis is called the xaxis, the vertical axis is called the yaxis, and their point of intersection is called the origin These axes divide the plane into four quadrants, as shown in Figure 71
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The square of the distance between an input and the point of the graph it corresponds to Show answer When the point is far from the origin, the function will look like , which is nearly zero This means the distance between the graph and the plane at those points will be tinyAnswer to Use polar coordinates to compute the region bounded by the graphs of x^2 y^2 = 4,\ y = \sqrt{3}x,\ y = 4, \text{ and } y = x ByX 2 4 y 2 9 z 2 = 1 Multiply both sides of the equation by 36, the least common multiple of 4,9 Multiply both sides of the equation by 3 6, the least common multiple of 4, 9 36x^ {2}9y^ {2}4z^ {2}=36 3 6 x 2 9 y 2 4 z 2 = 3 6 Subtract 36x^ {2} from both sides Subtract 3
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This is a circle of radius 4 centred at the origin Given x^2y^2=16 Note that we can rewrite this equation as (x0)^2(y0)^2 = 4^2 This is in the standard form (xh)^2(yk)^2 = r^2 of a circle with centre (h, k) = (0, 0) and radius r = 4 So this is a circle of radius 4 centred at the origin graph{x^2y^2 = 16 10, 10, 5, 5}% Find function value everywhere in the domain contour (X,Y,Z, 4 4) % Plot the isoline where the function value is 4 If you know more about your function and can turn it around into a function of only one variable (eg, sineCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
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Z = X^2 Y^2; 3D and Contour Grapher A graph in 3 dimensions is written in general z = f(x, y)That is, the zvalue is found by substituting in both an xvalue and a yvalue The first example we see below is the graph of z = sin(x) sin(y)It's a function of x and y You can use the following applet to explore 3D graphs and even create your own, using variables x and yTo get a sense of the behavior of exponential decay, we can create a table of values for a function of the form f (x)= bx f ( x) = b x whose base is between zero and one We'll use the function g(x) =(1 2)x g ( x) = ( 1 2) x Observe how the output values in (Figure) change as the input increases by 1
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Answer and Explanation 1 Given x2y2 =4 x 2 y 2 = 4 A circle with radius 2 2 units y = √3x, y = x y = 3 x, y = x Lines y = 4 y = 4 A line parallel to x x axis The graph of the(e) Below is the graph of z = x2 y2 On the graph of the surface, sketch the traces that you found in parts (a) and (c) For problems 1213, nd an equation of the trace of the surface in the indicated plane Describe the graph of the trace 12 Surface 8x 2 y z2 = 9;Make a table of points by choosing values for the xcoordinate Then substitute each into the equation y=x 4 to find the value for the ycoordinate x y=x 4 point 4 12 (4,12) 3 5 (3,5) 2 0 (2
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2x2y=4 Geometric figure Straight Line Slope = 1 xintercept = 2/1 = 0000 yintercept = 2/1 = 0000 Rearrange Rearrange the equation by subtracting what is to the right of theSurfaces and Contour Plots Part 4 Graphs of Functions of Two Variables The graph of a function z = f(x,y) is also the graph of an equation in three variables and is therefore a surfaceSince each pair (x,y) in the domain determines a unique value of z, the graph of a function must satisfy the "vertical line test" already familiar from singlevariable calculusSee the answer graph x^2y^2=4 in 3D, aka xyz aka R3 Expert Answer 100% (1 rating) Previous question Next question Get more help from Chegg Solve it with our calculus problem solver and calculator
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It is the equation of a circle Probably you can recognize it as the equation of a circle with radius r=1 and center at the origin, (0,0) The general equation of the circle of radius r and center at (h,k) is (xh)^2(yk)^2=r^2 Graphs a circle with centre (2,5) and the radius r=3 This equation can be recognised as the equation of a circle see Conic sections for a description of the patterns of the conic equations We need to reorganise and simplify it in order to get it into the standard form for a circle that will give us the centre and radius, after which it will be very easy to graph x^2 4xCircle on a Graph Let us put a circle of radius 5 on a graph Now let's work out exactly where all the points are We make a rightangled triangle And then use Pythagoras x 2 y 2 = 5 2 There are an infinite number of those points, here are some examples
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history See the explanantion This is the equation of a circle with its centre at the origin Think of the axis as the sides of a triangle with the Hypotenuse being the line from the centre to the point on the circle By using Pythagoras you would end up with the equation given where the 4 is in fact r^2 To obtain the plot points manipulate the equation as below Given" "x^2y^2=r^2" ">" "x^2y^2 =4This tool graphs z = f (x,y) mathematical functions in 3D It is more of a tour than a tool All functions can be set different boundaries for x, y, and z, to maximize your viewing enjoyment This tool looks really great with a very high detail level, but you may find it more comfortable to use less detail if you want to spin the model
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Related Queries rotate y=x^2 from x=1 to 1 about the yaxis;Answer to Sketch the graph of the function f(x,y) = \sqrt{x^2y^24} State the domain and range By signing up, you'll get thousands of All of the following graphs have the same size and shape as the above curve I am just moving that curve around to show you how it works Example 2 y = x 2 − 2 The only difference with the first graph that I drew (y = x 2) and this one (y = x 2 − 2) is the "minus 2" The "minus 2" means that all the yvalues for the graph need to be moved
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Graph x^2y^2=4 x2 − y2 = 4 x 2 y 2 = 4 Find the standard form of the hyperbola Tap for more steps Divide each term by 4 4 to make the right side equal to one x 2 4 − y 2 4 = 4 4 x 2 4 y 2 4 = 4 4 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola requiresGraph X^2y^2=4 In 3D, Aka Xyz Aka R3; It is an equation of a circle with center in C=(2;1) and radius r=3 From this form you can find out that the equation represents a circle To find its coordinates and radius you should transform it to form of (xa)^2(yb)^2=r^2 (1) We start from the equation given x^2y^24x2y4=0 Now we can group terms with the same variable x^24xy^22y4=0 Now we can complete
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